3y(1+y-y^2)=-y^2(2-3y)

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Solution for 3y(1+y-y^2)=-y^2(2-3y) equation: 



3y(1+y-y^2)=-y^2(2-3y)

We move all terms to the left:

3y(1+y-y^2)-(-y^2(2-3y))=0

We add all the numbers together, and all the variables

3y(1+y-y^2)-(-y^2(-3y+2))=0

We multiply parentheses

3y^2-3y^3-(-y^2(-3y+2))+3y=0



We calculate terms in parentheses: -(-y^2(-3y+2)), so:

-y^2(-3y+2)



We do not support eypression: y^3

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